Fixed: Album API query by foreignId only returns requested album

Setting the new 'includeAllArtistAlbums' will give the existing
behaviour of returning all albums for that artist
pull/6/head
ta264 6 years ago
parent 11c0f1dad2
commit 7b288bfcd3

@ -55,7 +55,10 @@ class AlbumDetailsPageConnector extends Component {
populate = () => {
const foreignAlbumId = this.props.foreignAlbumId;
this.setState({ hasMounted: true });
this.props.fetchAlbums({ foreignAlbumId });
this.props.fetchAlbums({
foreignAlbumId,
includeAllArtistAlbums: true
});
}
unpopulate = () => {

@ -42,6 +42,7 @@ namespace Lidarr.Api.V1.Albums
var artistIdQuery = Request.Query.ArtistId;
var albumIdsQuery = Request.Query.AlbumIds;
var foreignIdQuery = Request.Query.ForeignAlbumId;
var includeAllArtistAlbumsQuery = Request.Query.IncludeAllArtistAlbums;
if (!Request.Query.ArtistId.HasValue && !albumIdsQuery.HasValue && !foreignIdQuery.HasValue)
{
@ -57,9 +58,18 @@ namespace Lidarr.Api.V1.Albums
if (foreignIdQuery.HasValue)
{
int artistId = _albumService.FindById(foreignIdQuery.Value).ArtistId;
return MapToResource(_albumService.GetAlbumsByArtist(artistId), false);
string foreignAlbumId = foreignIdQuery.Value.ToString();
var album = _albumService.FindById(foreignAlbumId);
if (includeAllArtistAlbumsQuery.HasValue && Convert.ToBoolean(includeAllArtistAlbumsQuery.Value))
{
return MapToResource(_albumService.GetAlbumsByArtist(album.ArtistId), false);
}
else
{
return MapToResource(new List<Album> { album }, false);
}
}
string albumIdsValue = albumIdsQuery.Value.ToString();

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