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import re
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from functools import lru_cache
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from typing import Callable, List
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from ._cell_widths import CELL_WIDTHS
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# Regex to match sequence of the most common character ranges
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_is_single_cell_widths = re.compile("^[\u0020-\u006f\u00a0\u02ff\u0370-\u0482]*$").match
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@lru_cache(4096)
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def cached_cell_len(text: str) -> int:
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"""Get the number of cells required to display text.
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This method always caches, which may use up a lot of memory. It is recommended to use
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`cell_len` over this method.
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Args:
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text (str): Text to display.
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Returns:
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int: Get the number of cells required to display text.
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"""
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_get_size = get_character_cell_size
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total_size = sum(_get_size(character) for character in text)
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return total_size
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def cell_len(text: str, _cell_len: Callable[[str], int] = cached_cell_len) -> int:
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"""Get the number of cells required to display text.
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Args:
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text (str): Text to display.
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Returns:
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int: Get the number of cells required to display text.
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"""
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if len(text) < 512:
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return _cell_len(text)
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_get_size = get_character_cell_size
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total_size = sum(_get_size(character) for character in text)
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return total_size
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@lru_cache(maxsize=4096)
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def get_character_cell_size(character: str) -> int:
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"""Get the cell size of a character.
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Args:
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character (str): A single character.
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Returns:
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int: Number of cells (0, 1 or 2) occupied by that character.
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"""
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return _get_codepoint_cell_size(ord(character))
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@lru_cache(maxsize=4096)
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def _get_codepoint_cell_size(codepoint: int) -> int:
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"""Get the cell size of a character.
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Args:
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character (str): A single character.
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Returns:
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int: Number of cells (0, 1 or 2) occupied by that character.
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"""
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_table = CELL_WIDTHS
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lower_bound = 0
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upper_bound = len(_table) - 1
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index = (lower_bound + upper_bound) // 2
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while True:
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start, end, width = _table[index]
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if codepoint < start:
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upper_bound = index - 1
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elif codepoint > end:
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lower_bound = index + 1
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else:
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return 0 if width == -1 else width
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if upper_bound < lower_bound:
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break
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index = (lower_bound + upper_bound) // 2
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return 1
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def set_cell_size(text: str, total: int) -> str:
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"""Set the length of a string to fit within given number of cells."""
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if _is_single_cell_widths(text):
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size = len(text)
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if size < total:
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return text + " " * (total - size)
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return text[:total]
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if total <= 0:
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return ""
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cell_size = cell_len(text)
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if cell_size == total:
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return text
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if cell_size < total:
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return text + " " * (total - cell_size)
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start = 0
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end = len(text)
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# Binary search until we find the right size
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while True:
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pos = (start + end) // 2
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before = text[: pos + 1]
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before_len = cell_len(before)
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if before_len == total + 1 and cell_len(before[-1]) == 2:
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return before[:-1] + " "
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if before_len == total:
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return before
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if before_len > total:
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end = pos
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else:
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start = pos
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# TODO: This is inefficient
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# TODO: This might not work with CWJ type characters
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def chop_cells(text: str, max_size: int, position: int = 0) -> List[str]:
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"""Break text in to equal (cell) length strings, returning the characters in reverse
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order"""
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_get_character_cell_size = get_character_cell_size
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characters = [
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(character, _get_character_cell_size(character)) for character in text
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]
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total_size = position
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lines: List[List[str]] = [[]]
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append = lines[-1].append
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for character, size in reversed(characters):
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if total_size + size > max_size:
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lines.append([character])
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append = lines[-1].append
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total_size = size
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else:
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total_size += size
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append(character)
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return ["".join(line) for line in lines]
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if __name__ == "__main__": # pragma: no cover
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print(get_character_cell_size("😽"))
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for line in chop_cells("""这是对亚洲语言支持的测试。面对模棱两可的想法,拒绝猜测的诱惑。""", 8):
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print(line)
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for n in range(80, 1, -1):
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print(set_cell_size("""这是对亚洲语言支持的测试。面对模棱两可的想法,拒绝猜测的诱惑。""", n) + "|")
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print("x" * n)
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